Demonstration versions of the OGE in history (Grade 9). Demonstration options for the OGE in history (Grade 9) Demonstration options for the OGE in history
- a scale for recalculating the primary score for completing the 2020 examination paper into a mark on a five-point scale;
- a scale for recalculating the primary score for completing the 2019 examination paper into a mark on a five-point scale;
- a scale for recalculating the primary score for the completion of the examination paper in 2018 into a mark on a five-point scale;
- a scale for recalculating the primary score for the performance of the examination paper in 2017 into a mark on a five-point scale;
- a scale for recalculating the primary score for the performance of the examination paper in 2016 into a mark on a five-point scale;
- a scale for recalculating the primary score for the performance of the examination paper in 2015 into a mark on a five-point scale;
- a scale for recalculating the primary score for the performance of the examination paper in 2014 into a mark on a five-point scale;
- a scale for recalculating the primary score for the performance of the examination paper in 2013 into a mark on a five-point scale.
Changes in the demonstration versions of the OGE in physics
Demo Options OGE in physics 2009 - 2014 consisted of 3 parts: tasks with a choice of answers, tasks with a short answer, tasks with a detailed answer.
In 2013 in demo version of the OGE in physics the following changes:
- It was added task 8 with a choice of answers- on thermal phenomena,
- It was added task 23 with a short answer– understanding and analysis of experimental data presented in the form of a table, graph or figure (scheme),
- It was the number of tasks with a detailed answer has been increased to five: task 19 of part 1 was added to four tasks with a detailed answer of part 3 - on the use of information from the text of the physical content.
In 2014 demo version of the OGE in physics 2014 in relation to the previous year in terms of structure and content did not change, however, were criteria changed evaluation of tasks with a detailed answer.
In 2015, there was variant structure changed:
- Option became be in two parts.
- Numbering assignments has become through throughout the variant without letter designations A, B, C.
- The form of recording the answer in tasks with a choice of answers has been changed: the answer has become necessary to write digit with the number of the correct answer(not circled).
In 2016 in demo version of the OGE in physics happened significant changes:
- Total Jobs reduced to 26.
- Number of short answer items increased to 8
- Maximum score for all work did not change(still - 40 points).
AT demo versions of the OGE 2017 - 2019 in physics compared to 2016 demo there were no changes.
AT demo version of the OGE 2020 in physics compared to 2019 demo the structure has changed examination work:
Total number of jobs in the exam paper reduced from 26 to 25.
Quantity open-ended tasks It was increased from 5 to 6.
The requirements for completing experimental tasks have changed: it became mandatory to record direct measurements, taking into account the absolute error.
Introduced new criteria for evaluating experimental tasks. The maximum score for completing these tasks was 3.
Specification
control measuring materials for
in 2019 the main state exam in PHYSICS
1. Appointment of KIM for OGE- assess the level of general education in physics for ninth grade graduates educational organizations for the purpose of the state final certification of graduates. The results of the exam can be used when enrolling students in specialized classes high school.
OGE is conducted in accordance with the Federal Law Russian Federation dated December 29, 2012 No. 273-FZ “On Education in the Russian Federation”.
2. Documents defining the content of KIM
The content of the examination paper is determined on the basis of the Federal component state standard basic general education in physics (Order of the Ministry of Education of Russia dated 05.03.2004 No. 1089 “On Approval of the Federal Component of State Educational Standards for Primary General, Basic General and Secondary (Complete) General Education”).
3. Approaches to the selection of content, the development of the structure of KIM
The approaches to the selection of controlled content elements used in the design of CMM options ensure the requirement for the functional completeness of the test, since in each option the mastering of all sections of the basic school physics course is checked and tasks of all taxonomic levels are offered for each section. At the same time, the content elements that are most important from an ideological point of view or necessary for the successful continuation of education are checked in the same version of the KIM by tasks of different levels of complexity.
The structure of the KIM variant ensures the verification of all types of activities provided for by the Federal Component of the State Educational Standard (subject to the restrictions imposed by the conditions of mass written testing of students' knowledge and skills): mastering the conceptual apparatus of a basic school physics course, mastering methodological knowledge and experimental skills, using educational tasks of texts of physical content, the application of knowledge in solving computational problems and explaining physical phenomena and processes in practice-oriented situations.
The task models used in the examination work are designed for the use of blank technology (similar to the USE) and the possibility of automated verification of part 1 of the work. The objectivity of checking tasks with a detailed answer is ensured by uniform evaluation criteria and the participation of several independent experts who evaluate one work.
The OGE in physics is an exam of the choice of students and performs two main functions: final certification graduates of the basic school and the creation of conditions for the differentiation of students when entering the profile classes of the secondary school. For these purposes, KIM includes tasks of three levels of complexity. Completing tasks basic level complexity allows us to assess the level of mastering the most significant content elements of the standard in physics of the main school and mastering the most important species activities, and the performance of tasks of increased and high levels of complexity - the degree of readiness of the student to continue education at the next level of education, taking into account the further level of study of the subject (basic or profile).
4. Communication examination model OGE with KIM USE
Exam OGE model and KIM USE in physics are built on the basis of a single assessment concept educational achievements students in the subject "Physics". Uniform approaches are ensured primarily by checking all types of activities formed within the framework of teaching the subject. At the same time, similar work structures are used, as well as a single bank of job models. Continuity in formation various kinds activity is reflected in the content of tasks, as well as in the system for evaluating tasks with a detailed answer.
There are two significant differences between the exam model of the OGE and the KIM USE. So, technological features conducting the exam do not allow for full control of the formation of experimental skills, and this type of activity is checked indirectly using specially designed tasks based on photographs. Conducting the OGE does not contain such restrictions, therefore, an experimental task, which is performed on real equipment, has been introduced into the work. In addition, in the examination model of the OGE, a block for checking methods of working with various information of physical content is more widely represented.
5. Characteristics of the structure and content of KIM
Each CMM variant consists of two parts and contains 26 tasks that differ in form and level of complexity (Table 1).
Part 1 contains 22 tasks, of which 13 tasks are short answers in the form of one number, eight tasks require a short answer in the form of a number or a set of numbers, and one task is a detailed answer. Tasks 1, 6, 9, 15 and 19 with a short answer are tasks for establishing the correspondence of positions presented in two sets, or tasks for choosing two correct statements from the proposed list (multiple choice).
Part 2 contains four tasks (23-26), for which you need to provide a detailed answer. Task 23 is practical work for which laboratory equipment is used.
Main general education
Demo version of the OGE-2019 in physics
Demo version, codifier and specification of the OGE 2019 in physics from the official website of FIPI.Download the demo version of the OGE 2019 along with the codifier and specification from the link below:
Follow the information about our webinars and broadcasts on the YouTube channel, very soon we will discuss preparation for the OGE in physics.
The reference book is addressed to students of grade 9 to prepare for the OGE in physics. The manual contains detailed theoretical material on all topics tested by the exam, as well as training tasks in OGE form. Answers are provided at the end of the handbook. The publication will be useful to physics teachers, parents for the effective preparation of students for the OGE.
Analysis of the tasks of the demo version of the OGE in physics 2019
At this webinar, we will consider in detail all the tasks of the first part of the OGE in physics from 1 to 19. Each task will be given brief analysis, solution and answer. The demo version of the OGE-2019 itself is posted on the FIPI website. It exactly repeats the demo version of the OGE-2018, being its copy.
Exercise 1
For each physical concept from the first column, select the appropriate example from the second column.
Write in the table the selected numbers under the corresponding letters.
Solution
This task is quite simple, but in the collections for preparing for the OGE and in training options sometimes there are more complex tasks that require knowledge of the definitions of various physical concepts, terms, phenomena. In order for students to memorize these terms and their definitions well, it is best to keep a dictionary from grade 7 physical terms to make it easier for students to learn the most important theoretical concepts, laws, remember the definitions of physical quantities and phenomena. In this case, the physical quantity (that is, what can be measured) is mass, the unit of physical quantity (that is, what can be measured) is the newton (unit of force), and the instrument (what can be measured) are scales.
Answer: 315.
The figure shows graphs of the change in air pressure Δ p from time t for sound waves emitted by two tuning forks. Compare the amplitude of the pressure change and the pitch of the waves.
- The amplitude of pressure change is the same; the pitch of the first sound is greater than the second.
- The pitch is the same; the amplitude of pressure change in the first wave is less than in the second.
- The amplitude of the pressure change and the pitch are the same.
- The amplitude of the pressure change and the pitch are different.
Solution
In this task, students' knowledge on the topic of vibrations and waves is tested. In fact, there is a lot to remember about hesitation in order to complete the task. Firstly, that the amplitude is the maximum value of the measured value, that is, the highest point on the graph, which means that the amplitude of oscillations in the first wave is greater than in the second. Students are also required to understand that the period of oscillations can be determined from the distance between the peaks of the graph along the time axis, and then it will be clear that in the first wave the period of oscillations is less, and since the frequency is inverse to the period, the frequency in the first wave is greater than in the second . And you also need to know that the pitch is determined by the frequency of oscillations and the higher the frequency, the higher the tone, and therefore the pitch of the first wave will be greater than the second. Thus, both the frequency and amplitude of oscillations in these waves will be different, and in the first wave both of these characteristics are greater than in the second.
Answer: 4.
Task 3
Which statement(s) is(are) true?
Strength gravity between earth and moon
A. depends on the masses of the Earth and the Moon.
B. is the reason for the rotation of the moon around the earth.
- only A
- only B
- neither A nor B
- both A and B
Solution
The law of universal gravitation, which is discussed in this assignment, is studied, for example, using Peryshkin's textbook in grade 9 and in sufficient detail. Here it is necessary to recall the law itself, which says that the force of mutual attraction between two bodies is directly proportional to the product of the masses of the bodies (and therefore depends on the masses of both bodies) and inversely proportional to the square of the distance between them. In addition, it is good if students understand that the cause of any change in speed, both in magnitude and in direction, is some kind of force, and in this case, it is the force of gravity that changes the direction of the Moon's speed, which is why the Moon rotates around the Earth. Therefore, both statements will be true.
Answer: 4.
body mass m thrown from the surface of the earth vertically upwards with an initial velocity v 0 , climbed to the maximum height h 0 . Air resistance is negligible. Total mechanical energy of the body at some intermediate height h is equal to
Solution
Task 4 is quite interesting and quite difficult, as it requires the student to have a fairly deep understanding of the essence of the law of conservation of mechanical energy. In my opinion, in many textbooks this law, examples of its application are given insufficient attention. Therefore, very often in such tasks, students make mistakes. To correctly complete this task, the student must understand well that when the body moves in the absence of air resistance, the total mechanical energy of the body at any point will be the same. This means that at some intermediate height h the body will have both potential energy and some kinetic energy, having some speed v. But in the answer options there is no formula with this speed v. Therefore, the total mechanical energy at some intermediate point can also be equated to the initial kinetic energy ( mv 0 2 /2), and to the final (at the top point) potential ( mgh 0).
Answer: 2.
Cylinder 1 is weighed alternately with cylinder 2 of the same volume, and then with cylinder 3, which has a smaller volume (see figure).
Cylinder(s) have a maximum average density
- 1 and 3
Solution
In this task, the student is required to have a very good understanding of the relationship between such quantities as mass, volume and density of the body. He needs to be well versed with such concepts as directly proportional quantities and inversely proportional quantities. And although this topic is also in the 6th grade mathematics course, we often have to talk about it in physics lessons. Based on the definition of density as the ratio of mass to volume, we can conclude that when equal volumes first and second bodies, the first has a greater mass than the second, and therefore, greater density because the density is directly proportional to the mass of the body. But at equal mass of the third and first bodies, the third has a smaller volume, and therefore a greater density than the first, since the density of the body is inversely proportional to the volume. So body 3 will have the maximum density.
Answer: 3.
On a body at rest, located on a smooth horizontal plane, at the time t= 0, two horizontal forces begin to act (see figure). Determine how the modulus of the body's velocity and the modulus of the body's acceleration then change with time.
- increases
- decreases
- does not change
Solution
This problem is devoted to Newton's second law and the rule for calculating the resultant force. The concepts of vector and vector projection are quite difficult for many 9th graders. Therefore, I try to get around these concepts. To this end, I formulate fairly simple and understandable rules for calculating the resultant force:
- if the forces are directed in one direction, their values \u200b\u200bmust be added;
- if in opposite - subtract;
- if the forces are perpendicular to the motion of the body, then they do not participate in the calculation of the resultant. In accordance with the second rule, in this case we get that F total (this is how I designate the resultant force) \u003d 2.5 - 1 \u003d 1.5 N. And since F total is not equal to zero, then the acceleration of the body will also not be equal to zero, which means that the body will move uniformly accelerated (movement with variable acceleration is unknown to 9th graders). That is, the acceleration will be unchanged, but the speed of the body, since it was at rest at the beginning, will increase.
Answer: 13.
A cylinder was attached to the dynamometer, as shown in Figure 1. Then the cylinder was submerged in water (Figure 2).
Determine the volume of the cylinder.
Answer: ___________ cm 3.
Solution
Task 7 is always a task in mechanics. In this case, this task is an illustration laboratory work by measuring the buoyant (Archimedean) force, which is carried out according to any program and with any textbooks in the 7th grade. In Figure 1, the dynamometer determines the weight of the body in the air - R 1 \u003d 8 N, and in Figure 2 the weight of the body in the liquid is determined - R 2 \u003d 3 N, therefore the Archimedean force is equal to their difference F arch \u003d 8 - 3 \u003d 5 N. A similar laboratory work can be encountered by students at the exam itself in task 23. But here, in addition to the definition of the Archimedean strength, you need to use its formula:
F ar = ρ w g V burial
It is necessary to express the volume of the body from this formula, calculate it and convert the resulting answer from cubic meters to cubic centimeters. Thus, in order to cope with this task, the student must know the very formula of the Archimedean force, be able to transform formulas, expressing other quantities from them, and be able to convert one unit of measurement into another. All this is quite difficult for many children, and therefore this task belongs to tasks of increased difficulty. But then the question arises why it is estimated at only one point, if in other tasks to get the same one point it is enough just to guess the correct option and that's it. This is more than strange.
Answer: 500 cm3.
Task 8
One of the provisions of the molecular-kinetic theory of the structure of matter is that "particles of matter (molecules, atoms, ions) are in continuous chaotic motion." What do the words "continuous movement" mean?
- Particles always move in a certain direction.
- The movement of particles of matter is not subject to any laws.
- The particles all move together in one direction or the other.
- The movement of molecules never stops.
Solution
And here is an example of a task for which you can get 1 point, almost without thinking and without knowing anything about the provisions of the molecular kinetic theory. You just need to understand the meaning of the phrase "continuous movement" and guess that this is a movement that never stops. That is, this task has little to do with physics. It is rather a task in literature - to understand the meaning of the phrase. And compare this task with the previous one. Is it reasonable to evaluate both tasks equally at 1 point? I don't think.
Answer: 4.
Using the graph data, select from the proposed list two true statements. List their numbers.
- The initial temperature of the water is t 1 .
- The BV section corresponds to the process of water crystallization in the calorimeter.
- Point B corresponds to the time when the state of thermal equilibrium was established in the water-ice system.
- By the time thermal equilibrium was established, all the ice in the calorimeter had melted.
- The process corresponding to section AB proceeds with the absorption of energy.
Solution
Task 9 involves testing the ability of students to analyze the graph of changes in body temperature and determine the ongoing processes according to the graph. Spend more study time graphics tasks and this skill would be perfectly formed, but this is what teachers sorely lack - time. That is why even in such seemingly completely uncomplicated tasks, students make mistakes. In this case, section AB corresponds to the process of cooling water from t 1 °С to 0 °С, the BV section corresponds to the process of water crystallization, and the GV section corresponds to the process of heating ice from t 2 to 0 °С.
Answer: 12.
The figure shows a graph of the dependence of temperature t solid body from the amount of heat received by him Q. Body weight 2 kg. What is the specific heat capacity of the substance of this body?
Solution
And in this task, or rather the task, it is necessary to determine the initial body temperature according to the schedule t 1 = 150 °C, final body temperature t 2 \u003d 200 ° C and the amount of heat received by the body Q= 50 kJ. Then convert the amount of heat to joules: Q= 50,000 J. And then, as in problem 7, transform the formula, expressing from it the specific heat of the substance:
Q = With· m·( t 2 – t 1)
As you can see, here you also need to be able to convert values from one unit to another, and convert formulas, and the task is estimated at only 1 point.
Answer: 500.
Task 11
A metal plate, which had a positive charge, modulo 10 e, lost six electrons when illuminated. What is the charge on the plate?
- +16 e
- -16 e
Solution
This is a fairly simple task to understand the physical meaning of the concept of charge. The presence of a charge on a body means a lack (positive charge) or an excess (negative charge) of electrons on its surface. If students remember well that the charge of an electron is negative both from the physics course and from the chemistry course, then they will easily understand that since the plate had a positive charge of 10 e, this means that it lost 10 electrons. And since it lost six more electrons during illumination, its charge will become +16 e.
Answer: 3.
The figure shows a diagram of an electrical circuit consisting of three resistors and two keys K1 and K2. To the dots BUT and AT a constant voltage is applied. The maximum amount of heat released in the circuit in 1 s can be obtained by
- if only key K1 is closed
- if only key K2 is closed
- if both keys are closed
- if both keys are open
Solution
This task, in my opinion, is far from the easiest for a student. And again the question of the adequacy of the assessment arises. Here the student should see that when the keys are closed, other resistors will be added to the lower resistor in parallel. In doing so, he must remember that adding a resistor in parallel reduces the total resistance of the circuit, since 1/ R = 1/R 1 + 1/R 2 + … And this is not easy to remember and understand. Further, in accordance with Ohm's law for the chain section I = U/R, a decrease in the total resistance of the circuit leads to an increase in the current strength in the circuit. So, the student should have a pretty good idea of the inverse relationship between current and resistance. Finally, according to the Joule-Lenz law, Q = I 2 Rt, which means that an increase in current strength will lead to an increase in the amount of heat released (a decrease in resistance has little effect, since the amount of heat is directly proportional to the square of the current strength). It means that in the chain it stands out maximum amount heat, the resistance of the circuit should be minimal, which means that the circuit should contain the maximum number of resistors connected in parallel. That is, you need to close both keys. Agree, a very difficult task for any student, unless you do it at random.
Answer: 3.
Permanent magnet north pole introduced into a coil closed to a galvanometer (see figure).
If you bring the magnet into the coil with the south pole at the same speed, then the readings of the galvanometer will approximately correspond to the figure.
Solution
This task is best done experimentally. And even the study of the topic "Electromagnetic induction", I think, should not go beyond the scope of the experiment. For students in grades 8–9, this is quite enough to know that when the magnet moves inside the coil, an electric induction current begins to flow through it and that the direction of this current changes to the opposite when the direction of movement of the magnet itself changes or when the poles change, and the deflection angle of the milliammeter needle (galvanometer) depends on the speed of the magnet. Children learn all this very well when they do these experiments with their own hands and see everything with their own eyes. And it is not at all necessary in the framework of the study of this topic to introduce the concepts magnetic flux and EMF of induction - this is redundant on this stage learning. So those who have done such experiments on their own know for sure that if a magnet is introduced into the coil with the other pole at the same speed, then the galvanometer needle will deviate by the same angle, but in the opposite direction.
Answer: 2.
The figure shows three objects: A, B and C. The image of which object (s) in a thin converging lens, the focal length of which F, will be reduced, inverted and real?
- only A
- only B
- only in
- all three items
Solution
A fairly simple task for those who either know how to build an image in a lens using two beams, or who have done an experiment to obtain an image in a converging lens on a screen on their own. In both cases, it will be easy to understand that the image is reduced, inverted and real only if the object is located behind the double focus of the converging lens. It must be said that such an experiment can be caught by the student during the exam itself, so when preparing for the exam, it is advisable to conduct all possible experiments and laboratory work again together with the teacher or tutor, if this is possible.
Answer: 1.
Task 15
The man looks from the page of the book to the clouds outside the window. How does the focal length and optical power of the lens of the human eye change in this case?
Match between physical quantities and their possible changes.
For each value, determine the appropriate nature of the change:
- increases
- decreases
- does not change
Write in the table the selected numbers for each physical quantity.
Numbers in the answer may be repeated.
Solution
Here I would like to be very indignant towards the developers of KIMs. Do they really think that a ninth-grader should know by heart the contents of 7th, 8th and 9th grade physics textbooks?! Indeed, about the phenomenon of accommodation described in this task in any textbook of any author, there will not be more than two or three sentences. I think this kind of assignments are incorrect in relation to students. But in this case, one thing can be said - the student will have to be guided only by the logic and formula of the optical power of the lens D = 1/F. The closer the object is, the shorter the focal length should be, because this object must in any case be behind the double focus of the lens. This means that if you shift your gaze from a nearby object (book page) to a distant one (clouds), then the focal length should increase. And since the optical power is inverse to the focal length, it will, on the contrary, decrease.
Answer: 12
Task 16
The electric motor operates at a voltage of 220 V and a current of 40 A. What is the net power of the motor if it is known that its efficiency is 75%?
Answer: _______ kW.
Solution
This task again shows us the inadequacy of estimation, as well as tasks 7 and 10. Only one point for the task in which it is necessary to transform the efficiency formula, expressing the useful power from it. I will add to this the fact that not a single textbook says that the efficiency can be calculated as the ratio of useful power to total, but only as the ratio of useful work to total. That is, the student learns this only on the condition that he has solved a sufficiently large number of problems in which the efficiency factor was calculated not only as the ratio of work, but also as the ratio of powers. Let's ask the question - did the teacher have enough time to solve such problems? Hardly. In addition to difficulties with the efficiency formula, in this task the student must remember and apply the current power formula R = UI. Further, expressing the useful power R n = UI(here n is the designation of efficiency), it must not only be calculated, but also converted from watts to kilowatts.
Answer: 6,6.
Task 17
The following nuclear reaction took place: What particle X was released as a result of the reaction?
- α-particle
- β particle
- neutron
- proton
Solution
For the correct solution of this task, the student needs to know the laws of conservation of mass and charge numbers, as well as the designations of some particles. In accordance with the laws of conservation of the mass (upper) and charge (lower) numbers, we obtain that the mass and charge of the formed particle are equal to 1. Therefore, this particle will be a proton.
Answer: 4.
Record the result of the measurement of atmospheric pressure using an aneroid barometer (see figure), bearing in mind that the measurement error is equal to the price of pressure.
- (750 ± 5) mmHg Art.
- (755 ± 1) mmHg Art.
- (107 ± 1) Pa
- (100.7 ± 0.1) Pa
Solution
But I think there should be as many tasks as possible in the exam. I am convinced that the ability to use various measuring instruments and determine their readings is one of the most important skills that students should master as a result of studying physics in basic school. This skill includes determining the desired scale, if the device has two of them, determining the scale division value, understanding the concept of instrument error and its relationship with the division value, and taking the readings themselves. Unfortunately, in this task there is absolutely no test of the ability to determine the error and associate it with the division value. Because the answer options are formulated in such a way that it is enough for the student to notice two simple things - firstly, that the upper scale is graduated in kilopascals (there is a signature x1000 Pa in front of the scale), and there are no kilopascals in the answer options, and secondly, that the arrow of the device is exactly in the middle between the marks 750 and 760, which means that the device shows 755 mm Hg. Art., which immediately gives an answer to the question and does not require to determine either the division value or the error of the instrument.
Answer: 2.
The teacher at the lesson consistently conducted experiments to measure the force of sliding friction with a uniform movement of a bar with a load on two different horizontal surfaces (see figure).
From the proposed list, select two statements that are consistent with the experiments. List their numbers.
- The force of friction depends on the mass of the bar with the load.
- The force of friction depends on the speed of movement of the bar.
- The friction force depends on the angle of inclination of the displacement plane.
- The force of friction depends on the surface on which the block moves.
- The sliding friction for the second surface is greater.
Solution
In this task, the student is required to analyze the result of some experiment and choose the right conclusions about the observed dependencies. The correctness of the performance of such a task depends on how well the student has formed the ability to draw conclusions about dependencies based on the results of the experiment. To do this, in my practice, when conducting each laboratory work, at the end I ask all the guys to write, as a conclusion, the answers to some questions, which I myself compose for each laboratory work. The questions are designed in such a way that students need to draw conclusions about how one value depends on another, or does not depend, or it is impossible to draw such a conclusion, since the conditions of the experiment do not allow it. For example, in this task, in two experiments, the friction force was measured, while only the materials of the surface along which the bar moved were changed in the experiments. This means that, based on the results of such experiments, it is impossible to conclude either about the dependence of the friction force on the mass of the load, or about the dependence of the friction force on the speed of movement, or about the dependence of the friction force on the angle of inclination of the surface.
Answer: 45.
We reviewed all tasks from 1 to 19, solved them, analyzed some of the features of these tasks, discussed the adequacy of assessment (more precisely, its absence). This concludes our webinar. Next time we will take a closer look at the tasks of the second part of the physics exam in grade 9 - these are tasks from 23 to 26.
In conclusion, I will say that I categorically do not accept tasks 20–22 and fundamentally disagree with the developers that such tasks should generally be in KIMs. I consider them not only useless, but also dangerous, since they only increase the stress of the student, who has to read an obscure and completely unfamiliar scientific text, and even answer questions about this text. Such tasks have no place in the OGE in physics. Such tasks can be used in various kinds of research, where it is necessary to identify the ability of students to work with unfamiliar or completely unfamiliar text, understand its content and meaning, and analyze it. But on the exam in physics for the course of the basic school, there should be only those tasks, the content of which does not go beyond the scope of this course itself. This should be the main condition. And tasks 20–22 violate this most important condition.
Thank you for your attention. See you soon at our webinars.
Before the start of a new school year published on the official website of FIPI OGE demos 2019 in physics (GIA grade 9).
results OGE exam in physics in the 9th grade can be used when enrolling students in specialized classes of a secondary school. The benchmark for selection in specialized classes can be an indicator, the lower limit of which corresponds to 30 points.
Demo version of the OGE in physics 2019 (Grade 9) from FIPI with answers
Demo version of OGE 2019 in physics | option + answers |
Specification | download |
Codifier | download |
Changes in KIM 2019 compared to 2018
There are no changes in the structure and content of KIM.
Characteristics of the structure and content of KIM OGE 2019 in physics
Each CIM variant consists of two parts and contains 26 tasks that differ in form and level of complexity.
Part 1 contains 22 tasks, of which 13 tasks have a short answer in the form of a single number, eight tasks that require a short answer in the form of a number or a set of numbers, and one task with a detailed answer. Tasks 1, 6, 9, 15 and 19 with a short answer are tasks for establishing the correspondence of positions presented in two sets, or tasks for choosing two correct statements from the proposed list (multiple choice).
Part 2 contains four tasks (23-26), for which you need to provide a detailed answer. Task 23 is a laboratory work for which laboratory equipment is used.
The duration of the OGE in physics
Estimated time to complete tasks is:
1) for tasks of a basic level of complexity - from 2 to 5 minutes;
2) for tasks increased complexity– from 6 to 15 minutes;
3) for tasks high level difficulty - from 20 to 30 minutes.
180 minutes are allotted to complete the entire examination paper.
Exam conditions
The exam is held in physics classrooms. If necessary, you can use other rooms that meet the requirements of safe work when performing experimental tasks of the examination work.
At the exam, in each classroom there is a specialist instructing and providing laboratory work, who conducts safety briefing before the exam and monitors compliance with the rules of safe work during the work of students with laboratory equipment.
Sample safety instructions are given in Appendix 3*.
Sets of laboratory equipment for performing laboratory work (task 23) are formed in advance, before the exam. For the preparation of laboratory equipment, one or two days before the exam, the numbers of the equipment sets that will be used in the exam are reported to the venues.
The criteria for verifying the performance of laboratory work require the use of standardized laboratory equipment within the framework of the OGE. The list of equipment sets for performing experimental tasks was compiled on the basis of standard sets for frontal work in physics, as well as on the basis of the GIA Laboratory sets. The composition of these sets / kits meets the requirements of reliability and the requirements for the design of experimental tasks of the bank of examination tasks for the OGE.
Numbers and descriptions of the equipment included in the kits are given in Appendix 2* “List of equipment kits”.
In the absence of any devices and materials at the examination points, the equipment can be replaced with a similar one with different characteristics. In order to ensure an objective assessment of the performance of laboratory work OGE participants in the case of replacing equipment with a similar one with different characteristics, it is necessary to bring to the attention of the experts of the subject committee who check the performance of tasks, a description of the characteristics of the equipment actually used in the exam.
* see demo
On the official website of the Federal Institute of Pedagogical Measurements (FIPI) published demonstration versions of the OGE in history (grade 9) for 2009 - 2020.
Demonstration versions of the OGE in history contain tasks of three types: tasks where you need to choose one of the proposed answers, tasks where you need to give a short answer, and tasks where you need to give a detailed answer. The tasks of the first and second types were given the correct answers, and the content of the correct answer and the evaluation criteria were given to the tasks of the third type.
AT one model CMM corresponding
saved
new tasks introduced
increased
allocated task block,
expanded
Demonstration versions of the OGE in history
Note that demonstration versions of the OGE in history are presented in pdf format, and to view them you need to have installed, for example, the freely distributed software package Adobe Reader on your computer.
Demonstration version of the OGE in history for 2009 | |
Demonstration version of the OGE in history for 2010 | |
Demonstration version of the OGE in history for 2011 | |
Demonstration version of the OGE in history for 2012 | |
Demonstration version of the OGE in history for 2013 | |
Demonstration version of the OGE in history for 2014 | |
Demonstration version of the OGE in history for 2015 | |
Demonstration version of the OGE in history for 2016 | |
Demonstration version of the OGE in history for 2017 | |
Demonstration version of the OGE in history for 2018 | |
Demonstration version of the OGE in history for 2019 (model 1) | |
Demonstration version of the OGE in history for 2019 (model 2) | |
Demonstration version of the OGE in history for 2020 |
Primary score recalculation scale
- for completing the exam 2020 in the mark on a five-point scale;
- primary score scale for completing the exam 2019 in the mark on a five-point scale;
- primary score scale for completing the exam 2018 in the mark on a five-point scale;
- primary score scale for completing the exam 2017 in the mark on a five-point scale;
- primary score scale for completing the exam 2016 on a five-point scale.
- primary score scale for completing the exam 2015 on a five-point scale.
- primary score scale for completing the exam 2014 on a five-point scale.
- primary score scale for completing the exam year 2013 on a five-point scale.
History demo changes
In 2015 in demo version of the OGE in history was variant structure changed:
The variant began to consist in two parts.
Numbering assignments has become through throughout the variant without letter designations A, B, C.
The form of recording the answer in tasks with a choice of answers has been changed: the answer has become necessary to write digit with the number of the correct answer(not circled).
The periodization of the sections of the work was brought in line with the Historical and Cultural Standard (the third section starts from 1914, and not from 1917, as it was before).
The criteria for assessing task 35 have been finalized.
AT demo versions of the OGE 2016 in history compared to 2015 demos there are no substantive changes: only the order of several tasks of part 1 has been changed.
AT demo versions of the OGE 2017 - 2018 in history compared to 2016 demo there were no changes.
In 2019, in connection with the transition of some schools to a linear system of studying history, in 2019 two demo models: demo version No. 1, the tasks of which cover the course of history from ancient times to the present, and demo version No. 2, the tasks of which cover the course of history from ancient times to 1914.
AT demo version of the OGE 2020 in history compared to the 2019 demos, only one model CMM corresponding linear system history studies based on the Historical and Cultural Standard, in which
some tasks from the previous model were saved(tasks 2-5, 7, 11, 12, 20, 21).
new tasks introduced to work with a historical map,
increased number of tasks based on visual sources of historical information,
a block of tasks is selected, testing knowledge of cultural history,
expanded range of analytical tasks.